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Oracle Database SQL Sample Questions (Q196-Q201):
NEW QUESTION # 196
View the Exhibit and examine the structure of the ORDERS table.
You must select ORDER_ID and ORDER_DATE for all orders that were placed after the last order placed by CUSTOMER_ID 101.
Which query would give you the desired result?
- A. SELECT order_id, order_date FROM orders
WHERE order_date > IN
(SELECT order_date FROM orders WHERE customer_id = 101); - B. SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT order_date FROM orders WHERE customer_id = 101); - C. SELECT order_id, order_date FROM orders
WHERE order_date >
ANY
(SELECT order_date FROM orders WHERE customer_id = 101); - D. SELECT order_id, order_date FROM orders
WHERE order_date > ALL
(SELECT MAX(order_date) FROM orders ) AND customer_id = 101;
Answer: B
NEW QUESTION # 197
Examine this query which executes successfully;
Select job,deptno from emp
Union all
Select job,deptno from jobs_history;
What will be the result?
- A. It will return rows common to both select statements.
- B. It will return rows from both select statements after eliminating duplicate rows.
- C. It will return rows that are not common to both select statements.
- D. It will return rows both select statements including duplicate rows.
Answer: D
NEW QUESTION # 198
View the Exhibit and examine the ORDERS table.
The ORDERS table contains data and all orders have been assigned a customer ID. Which statement would add a NOT NULL constraint to the CUSTOMER_ID column?
- A. ALTER TABLE orders
MODIFY customer_id CONSTRAINT orders_cust_id_nn NOT NULL; - B. ALTER TABLE orders
ADD customer_id NUMBER(6)CONSTRAINT orders_cust_id_nn NOT NULL; - C. ALTER TABLE orders
MODIFY CONSTRAINT orders_cust_id_nn NOT NULL (customer_id); - D. ALTER TABLE orders
ADD CONSTRAINT orders_cust_id_nn NOT NULL (customer_id);
Answer: A
NEW QUESTION # 199
View the Exhibit and examine the data in the PRODUCTS table. (Choose the best answer.)
You must display product names from the PRODUCTS table that belong to the 'Software/other' category with minimum prices as either $2000 or $4000 and with no unit of measure.
You issue this query:
SQL > SELECT prod_name, prod_category, prod_min_price FROM products
Where prod_category LIKE '%Other%' AND (prod_min_price = 2000 OR prod_min_price = 4000) AND prod_unit_of_measure <> ' '; Which statement is true?
- A. It executes successfully but returns no result.
- B. It generates an error because the condition specified for PROD_UNIT_OF_MEASURE is not valid.
- C. It generates an error because the condition specified for the PROD_CATEGORY column is not valid.
- D. It executes successfully and returns the required result.
Answer: A
NEW QUESTION # 200
View the Exhibit and examine the structure of the CUSTOMERS table.
Using the CUSTOMERS table, you must generate a report that displays a credit limit increase of 15% for all customers.
Customers with no credit limit should have "Not Available" displayed.
Which SQL statement would produce the required result?
- A. SELECT NVL (cust_credit_limit, 'Not Available')*.15 "NEW CREDIT" FROM customers
- B. SELECT TO_CHAR(NVL(cust_credit_limit*.15), 'Not Available')) "NEW CREDIT" FROM customers
- C. SELECT NVL (cust_credit_limit*.15, 'Not Available') "NEW CREDIT" FROM customers
- D. SELECT NVL (TO_CHAR(cust_credit_limit*.15), 'Not Available') "NEW CREDIT" FROM customers
Answer: C
NEW QUESTION # 201
......
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